Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
αλλά | 516 | 17 | 1 | 17.0000 |
Η | 952 | 58 | 5 | 11.6000 |
Σε | 168 | 11 | 1 | 11.0000 |
Τα | 181 | 11 | 1 | 11.0000 |
Από | 163 | 11 | 1 | 11.0000 |
Ο | 777 | 39 | 4 | 9.7500 |
Το | 569 | 38 | 4 | 9.5000 |
Και | 157 | 9 | 1 | 9.0000 |
καθώς | 234 | 8 | 1 | 8.0000 |
Στο | 171 | 8 | 1 | 8.0000 |
Αυτό | 90 | 8 | 1 | 8.0000 |
Οι | 407 | 24 | 3 | 8.0000 |
Για | 173 | 14 | 2 | 7.0000 |
Στην | 120 | 7 | 1 | 7.0000 |
κι | 150 | 14 | 2 | 7.0000 |
όπως | 272 | 19 | 3 | 6.3333 |
όπου | 145 | 6 | 1 | 6.0000 |
επί | 77 | 6 | 1 | 6.0000 |
Είναι | 147 | 11 | 2 | 5.5000 |
δικό | 26 | 5 | 1 | 5.0000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
νέα | 113 | 1 | 7 | 0.1429 |
Συμβουλίου | 19 | 1 | 5 | 0.2000 |
δηλώσεις | 44 | 1 | 5 | 0.2000 |
έχουμε | 86 | 1 | 5 | 0.2000 |
σύστημα | 45 | 1 | 5 | 0.2000 |
πολιτική | 64 | 1 | 5 | 0.2000 |
θέματα | 43 | 1 | 5 | 0.2000 |
Ερντογάν | 33 | 1 | 5 | 0.2000 |
πρέπει | 265 | 2 | 9 | 0.2222 |
εβδομάδα | 29 | 1 | 4 | 0.2500 |
θέλω | 22 | 1 | 4 | 0.2500 |
αρχίσει | 17 | 1 | 4 | 0.2500 |
ώρες | 67 | 2 | 8 | 0.2500 |
όσοι | 38 | 1 | 4 | 0.2500 |
τώρα | 79 | 1 | 4 | 0.2500 |
ΠΑΕ | 23 | 1 | 4 | 0.2500 |
μπορεί | 190 | 2 | 8 | 0.2500 |
εφημερίδα | 31 | 1 | 4 | 0.2500 |
1-0 | 25 | 1 | 4 | 0.2500 |
μη | 46 | 1 | 4 | 0.2500 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II